[76.3.1.1] By virtue of the symmetry relation (6.5) the integral in
(7.4) may be written as
∫-∞∞xσhx;ϖ,ζ,0,1dx=∫0∞xσhx;ϖ,ζ,0,1dx+∫0∞xσhx;ϖ,-ζ,0,1dx | | (B.1) |
The definition (A.1) implies the general formula [32]
∫0∞xs-1HPQmn(ax|a1,A1…aP,APb1,B1…bQ,BQ)dx=a-s∏j=1mΓbj+Bjs∏j=1nΓ1-aj-Ajs∏j=m+1QΓ1-bj-Bjs∏j=n+1PΓaj+Ajs | | (B.2) |
by virtue of the Mellin inversion theorem.
[76.3.1.2] Specializing to the
case at hand
∫0∞xσhx;ϖ,ζ,0,1dx | =1ϖ∫0∞xσH2211(x|1-1/ϖ,1/ϖ1-ϱ,ϱ0,11-ϱ,ϱ)dx | | (B.3) |
| =Γσ+1Γ-σ/ϖϖΓ1+ϱσΓ-ϱσ | | (B.4) |
where ϱ=12-ζϖ+ζ2.
[76.3.1.3] Using ΓxΓ-x=-π/xsinπx and the functional
equation for the Γ-function gives
∫0∞xσhx;ϖ,ζ,0,1dx=1πsinπϱσΓσΓ1-σϖ | | (B.5) |
which inserted into (B.1) readily yields the desired
result (7.5).